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/* $NetBSD: fpu_div.c,v 1.4 2005/12/11 12:18:42 christos Exp $ */ /* * Copyright (c) 1992, 1993 * The Regents of the University of California. All rights reserved. * * This software was developed by the Computer Systems Engineering group * at Lawrence Berkeley Laboratory under DARPA contract BG 91-66 and * contributed to Berkeley. * * All advertising materials mentioning features or use of this software * must display the following acknowledgement: * This product includes software developed by the University of * California, Lawrence Berkeley Laboratory. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * 1. Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * 2. Redistributions in binary form must reproduce the above copyright * notice, this list of conditions and the following disclaimer in the * documentation and/or other materials provided with the distribution. * 3. Neither the name of the University nor the names of its contributors * may be used to endorse or promote products derived from this software * without specific prior written permission. * * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF * SUCH DAMAGE. * * @(#)fpu_div.c 8.1 (Berkeley) 6/11/93 */ /* * Perform an FPU divide (return x / y). */ #include <sys/cdefs.h> __FBSDID("$FreeBSD: release/9.1.0/sys/powerpc/fpu/fpu_div.c 178030 2008-04-09 08:50:37Z grehan $"); #include <sys/types.h> #include <sys/systm.h> #include <machine/fpu.h> #include <machine/reg.h> #include <powerpc/fpu/fpu_arith.h> #include <powerpc/fpu/fpu_emu.h> /* * Division of normal numbers is done as follows: * * x and y are floating point numbers, i.e., in the form 1.bbbb * 2^e. * If X and Y are the mantissas (1.bbbb's), the quotient is then: * * q = (X / Y) * 2^((x exponent) - (y exponent)) * * Since X and Y are both in [1.0,2.0), the quotient's mantissa (X / Y) * will be in [0.5,2.0). Moreover, it will be less than 1.0 if and only * if X < Y. In that case, it will have to be shifted left one bit to * become a normal number, and the exponent decremented. Thus, the * desired exponent is: * * left_shift = x->fp_mant < y->fp_mant; * result_exp = x->fp_exp - y->fp_exp - left_shift; * * The quotient mantissa X/Y can then be computed one bit at a time * using the following algorithm: * * Q = 0; -- Initial quotient. * R = X; -- Initial remainder, * if (left_shift) -- but fixed up in advance. * R *= 2; * for (bit = FP_NMANT; --bit >= 0; R *= 2) { * if (R >= Y) { * Q |= 1 << bit; * R -= Y; * } * } * * The subtraction R -= Y always removes the uppermost bit from R (and * can sometimes remove additional lower-order 1 bits); this proof is * left to the reader. * * This loop correctly calculates the guard and round bits since they are * included in the expanded internal representation. The sticky bit * is to be set if and only if any other bits beyond guard and round * would be set. From the above it is obvious that this is true if and * only if the remainder R is nonzero when the loop terminates. * * Examining the loop above, we can see that the quotient Q is built * one bit at a time ``from the top down''. This means that we can * dispense with the multi-word arithmetic and just build it one word * at a time, writing each result word when it is done. * * Furthermore, since X and Y are both in [1.0,2.0), we know that, * initially, R >= Y. (Recall that, if X < Y, R is set to X * 2 and * is therefore at in [2.0,4.0).) Thus Q is sure to have bit FP_NMANT-1 * set, and R can be set initially to either X - Y (when X >= Y) or * 2X - Y (when X < Y). In addition, comparing R and Y is difficult, * so we will simply calculate R - Y and see if that underflows. * This leads to the following revised version of the algorithm: * * R = X; * bit = FP_1; * D = R - Y; * if (D >= 0) { * result_exp = x->fp_exp - y->fp_exp; * R = D; * q = bit; * bit >>= 1; * } else { * result_exp = x->fp_exp - y->fp_exp - 1; * q = 0; * } * R <<= 1; * do { * D = R - Y; * if (D >= 0) { * q |= bit; * R = D; * } * R <<= 1; * } while ((bit >>= 1) != 0); * Q[0] = q; * for (i = 1; i < 4; i++) { * q = 0, bit = 1 << 31; * do { * D = R - Y; * if (D >= 0) { * q |= bit; * R = D; * } * R <<= 1; * } while ((bit >>= 1) != 0); * Q[i] = q; * } * * This can be refined just a bit further by moving the `R <<= 1' * calculations to the front of the do-loops and eliding the first one. * The process can be terminated immediately whenever R becomes 0, but * this is relatively rare, and we do not bother. */ struct fpn * fpu_div(struct fpemu *fe) { struct fpn *x = &fe->fe_f1, *y = &fe->fe_f2; u_int q, bit; u_int r0, r1, r2, r3, d0, d1, d2, d3, y0, y1, y2, y3; FPU_DECL_CARRY /* * Since divide is not commutative, we cannot just use ORDER. * Check either operand for NaN first; if there is at least one, * order the signalling one (if only one) onto the right, then * return it. Otherwise we have the following cases: * * Inf / Inf = NaN, plus NV exception * Inf / num = Inf [i.e., return x] * Inf / 0 = Inf [i.e., return x] * 0 / Inf = 0 [i.e., return x] * 0 / num = 0 [i.e., return x] * 0 / 0 = NaN, plus NV exception * num / Inf = 0 * num / num = num (do the divide) * num / 0 = Inf, plus DZ exception */ DPRINTF(FPE_REG, ("fpu_div:\n")); DUMPFPN(FPE_REG, x); DUMPFPN(FPE_REG, y); DPRINTF(FPE_REG, ("=>\n")); if (ISNAN(x) || ISNAN(y)) { ORDER(x, y); fe->fe_cx |= FPSCR_VXSNAN; DUMPFPN(FPE_REG, y); return (y); } /* * Need to split the following out cause they generate different * exceptions. */ if (ISINF(x)) { if (x->fp_class == y->fp_class) { fe->fe_cx |= FPSCR_VXIDI; return (fpu_newnan(fe)); } DUMPFPN(FPE_REG, x); return (x); } if (ISZERO(x)) { fe->fe_cx |= FPSCR_ZX; if (x->fp_class == y->fp_class) { fe->fe_cx |= FPSCR_VXZDZ; return (fpu_newnan(fe)); } DUMPFPN(FPE_REG, x); return (x); } /* all results at this point use XOR of operand signs */ x->fp_sign ^= y->fp_sign; if (ISINF(y)) { x->fp_class = FPC_ZERO; DUMPFPN(FPE_REG, x); return (x); } if (ISZERO(y)) { fe->fe_cx = FPSCR_ZX; x->fp_class = FPC_INF; DUMPFPN(FPE_REG, x); return (x); } /* * Macros for the divide. See comments at top for algorithm. * Note that we expand R, D, and Y here. */ #define SUBTRACT /* D = R - Y */ \ FPU_SUBS(d3, r3, y3); FPU_SUBCS(d2, r2, y2); \ FPU_SUBCS(d1, r1, y1); FPU_SUBC(d0, r0, y0) #define NONNEGATIVE /* D >= 0 */ \ ((int)d0 >= 0) #ifdef FPU_SHL1_BY_ADD #define SHL1 /* R <<= 1 */ \ FPU_ADDS(r3, r3, r3); FPU_ADDCS(r2, r2, r2); \ FPU_ADDCS(r1, r1, r1); FPU_ADDC(r0, r0, r0) #else #define SHL1 \ r0 = (r0 << 1) | (r1 >> 31), r1 = (r1 << 1) | (r2 >> 31), \ r2 = (r2 << 1) | (r3 >> 31), r3 <<= 1 #endif #define LOOP /* do ... while (bit >>= 1) */ \ do { \ SHL1; \ SUBTRACT; \ if (NONNEGATIVE) { \ q |= bit; \ r0 = d0, r1 = d1, r2 = d2, r3 = d3; \ } \ } while ((bit >>= 1) != 0) #define WORD(r, i) /* calculate r->fp_mant[i] */ \ q = 0; \ bit = 1 << 31; \ LOOP; \ (x)->fp_mant[i] = q /* Setup. Note that we put our result in x. */ r0 = x->fp_mant[0]; r1 = x->fp_mant[1]; r2 = x->fp_mant[2]; r3 = x->fp_mant[3]; y0 = y->fp_mant[0]; y1 = y->fp_mant[1]; y2 = y->fp_mant[2]; y3 = y->fp_mant[3]; bit = FP_1; SUBTRACT; if (NONNEGATIVE) { x->fp_exp -= y->fp_exp; r0 = d0, r1 = d1, r2 = d2, r3 = d3; q = bit; bit >>= 1; } else { x->fp_exp -= y->fp_exp + 1; q = 0; } LOOP; x->fp_mant[0] = q; WORD(x, 1); WORD(x, 2); WORD(x, 3); x->fp_sticky = r0 | r1 | r2 | r3; DUMPFPN(FPE_REG, x); return (x); }